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9x^2+4.7x-6=0
a = 9; b = 4.7; c = -6;
Δ = b2-4ac
Δ = 4.72-4·9·(-6)
Δ = 238.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.7)-\sqrt{238.09}}{2*9}=\frac{-4.7-\sqrt{238.09}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.7)+\sqrt{238.09}}{2*9}=\frac{-4.7+\sqrt{238.09}}{18} $
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